CHICAGO (CBSNewYork/AP) — Chicago Cubs third baseman Kris Bryant was named NL MVP on Thursday, while Los Angeles Angels center fielder Mike Trout won the honor for the AL for the second time in three years.

Bryant received 29 of 30 first-place votes for the National League Most Valuable Player, finishing with 415 total points, CBS Chicago reported.

Daniel Murphy of the Nationals was second and rookie Corey Seager of the Dodgers was third.

Cubs first baseman Anthony Rizzo was fourth with 202 points, CBS Chicago reported.

Bryant, 24, hit .292 with 39 home runs, 102 RBIs, 121 runs, and .939 OPS, CBS Chicago reported. The Cubs won the World Series for the first time since 1908 this year.

Bryant was the 10th Cubs player in history to win the MVP and the first since Sammy Sosa in 1998, CBS Chicago reported.

And while the Angels finished fourth in the AL West, Trout was his usual brilliant self. He batted .315 with 29 homers, 100 RBIs and 30 steals. He scored 17 percent of Los Angeles’ runs, the highest percentage for an AL player since Rickey Henderson with the 1985 New York Yankees.

Trout becomes the first MVP from a losing team since Alex Rodriguez for Texas in 2003. He received 19 of 30 first-place votes

Boston Red Sox right fielder Mookie Betts finished second. AL batting champion Jose Altuve of Houston was third. Retiring Red Sox slugger David Ortiz finished sixth in his final year in the majors.

(TM and © Copyright 2016 CBS Radio Inc. and its relevant subsidiaries. CBS RADIO and EYE Logo TM and Copyright 2016 CBS Broadcasting Inc. Used under license. All Rights Reserved. This material may not be published, broadcast, rewritten, or redistributed. The Associated Press contributed to this report.)